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3 February, 12:38

A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 * 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

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  1. 3 February, 12:39
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    Work done = force * distance moved (in direction of the force)

    force = mass * acceleration

    force=58.1N

    58.1 * (5.8*10^4)

    =3,369,800 J
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