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23 February, 22:32

The disks you will be using in the lab have the following parameters. All disks are solid with outer radius R1 = 0 0632 m and inner radius R2 = 0 0079 m The masses of the disks are: MT starless steel = 1357kg, MBottom starless stee,ã¼1.344kg. Calculate the moments of inertia of the disks.

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  1. 23 February, 22:51
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    MT disc I = 2,752 10-3 kg m²

    MB disc I = 2,726 10⁻³ kg m²

    Explanation:

    The moment of inertia given by the expression

    I = ∫ r² dm

    for bodies with high symmetry it is tabulated

    for a hollow disk it is

    I = ½ M (R₁² + R₂²)

    let's apply this equation to our case

    disc MT = 1,357 kg

    I = ½ 1,357 (0.0079² + 0.0632²)

    I = 2,752 10-3 kg m²

    disk MB = 1,344 kg

    I = ½ 1,344 (0.0079² + 0.0632²)

    I = 2,726 10⁻³ kg m²
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