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29 November, 18:32

You see lightning and 30 seconds later you hear thunder. how far away is the thunderstorm? take the speed of sound to be 339 m/s. g

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  1. 29 November, 18:48
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    Let the observer be 'd' distance away from the thunderstorm and let light take 't' time to reach the observer

    Since the speed of sound and light remains constant in a particular medium, we can use

    Speed = Distance/Time

    For light,

    3 x 10^8 = d/t

    t = d / (3 x 10^8) - 1

    For sound,

    339 = d / (t + 30) - 2

    Putting value from 1 in 2.

    d = 10^4 m (approx)
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