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14 May, 12:58

A temperature of a 50 kg block increases by 15°C when 337,500 J of thermal energy are added to the block.

a. What is the specific heat of the object? show your work with units.

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  1. 14 May, 13:25
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    Heat = mass * specific heat * temperature change

    q = m C ΔT

    Given:

    q = 337500 J

    m = 50 kg

    ΔT = 15°C

    Substitute:

    337500 J = (50 kg) C (15°C)

    C = 450 J/kg/°C

    Specific heat is usually recorded in J/g/°C or kJ/kg/°C. Converting:

    C = 0.45 J/g/°C = 0.45 kJ/kg/°C
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