A research submarine has a 10-cm-diameter window that is 8.4 cm thick. The manufacturer says the window can withstand forces up to 1.2*106 N. What is the submarine's maximum safe depth in salt water?

The pressure inside the submarine is maintained at 1.0 atm.

Express your answer using two significant figures.

Pnet = Po + dgh

Density of saltwater = 1030 kg/m^3.

Disregard the thickness. Assuming it's a circular window, then the area is pi (r^2).

d = 20 cm = 0.2 m

r = d/2 = 0.1 m

A = pi (r^2)

A = 3.14159265 (.1^2)

A = 0.0314159265 m^2

p = F/A

p = (1.1 x 10^6) / (0.0314159265)

p = 35,014,087.5 Pa

1 atm = 101,325 Pa

P = Po + dgh

h = (P - Po) / dg

h = (35,014,087.5 - 101,325) / (1030 x 9.81)

h = 3 455.23812 m

h = 3.5 km