Ask Question
26 April, 03:14

answers Collision derivation problem. If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 12/75, the initial displacement is 2.25 m, and the change in momentum is 0.58 kg*m/s, how far will it coast back up the ramp before changing directions?

+3
Answers (1)
  1. 26 April, 03:41
    0
    4.8967m

    Explanation:

    Given the following data;

    M = 0.2kg

    ∆p = 0.58kgm/s

    S (i) = 2.25m

    Ratio h/w = 12/75

    Firstly, we use conservation of momentum to find the velocity

    Therefore, ∆p = MV

    0.58kgm/s = 0.2V

    V = 0.58/2

    V = 2.9m/s

    Then, we can use the conservation of energy to solve for maximum height the car can go

    E (i) = E (f)

    1/2mV² = mgh

    Mass cancels out

    1/2V² = gh

    h = 1/2V²/g = V²/2g

    h = (2.9) ²/2 (9.8)

    h = 8.41/19.6 = 0.429m

    Since we have gotten the heigh, the next thing is to solve for actual slant of the ramp and initial displacement using similar triangles.

    h/w = 0.429/x

    X = 0.429*75/12

    X = 2.6815

    Therefore, by Pythagoreans rule

    S (ramp) = √2.68125²+0.429²

    S (ramp) = 2.64671

    Finally, S (t) = S (ramp) + S (i)

    = 2.64671+2.25

    = 4.8967m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “answers Collision derivation problem. If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 12/75, the initial ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers