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26 September, 04:51

A tuned mass damper for a skyscraper consists of a mass-spring system with spring constant 0.288 M/m. What should be its mass if it's to oscillate with a period of 5.91 s

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  1. 26 September, 05:06
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    m = 0.255kg

    Explanation:

    from the formular of a mass - spring system

    T = 2π√m/k

    making m as the subject of formular

    m = T² k/4π²

    T = 5.91s

    k = 0.288 N/m

    m = 10.059/39.489

    m = 0.255kg
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