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3 November, 16:48

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3, length 84.5 cm and diameter 2.40 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g = 9.80 m/s2.

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  1. 3 November, 16:53
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    29.22 N

    Explanation:

    Parameters given:

    Density = 7800 kg/m³

    Diameter of rod = 2.4cm = 0.024m

    Radius = 0.012m

    Length = 84.5cm = 0.845m

    To find the weight, we must find get the mass.

    Density is given as:

    Density = mass/volume

    Therefore, mass is:

    Mass = density * volume

    Volume of the cylindrical rod is:

    Volume = pi * r² * h

    Volume = 3.142 * 0.012² * 0.845

    Volume = 0.0003823 m³

    Mass = 7800 * 0.0003823

    Mass = 2.982 kg

    Weight = m * g

    Where g is acceleration due to gravity

    Weight = 2.982 * 9.8 = 29.22 N
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