A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.

What is the magnitude of the torque on the current loop?

Question

Cecilia Gibbs

Physics

4 August, 21:50

A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.

What is the magnitude of the torque on the current loop?

+1

Answers (1)

Know the Answer?

Sharon Hamilton · Answer 1

The magnitude of the torque on the current loop is 0.0055 Nm

Explanation:

Given data,

We have the formula,

T = u x B

Where u = i x A

T = i*A*B * sin (30)

T=0.46*0.52² * 0.900*0.5

T=0.0055 Nm

The magnitude of the torque on the current loop is 0.0055 Nm

A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.What is the magnitude of the torque on the current loop?

A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.

What is the magnitude of the torque on the current loop?