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13 January, 08:24

a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0 degree angle, against a 14.2 N friction force. find the work done by the friction force

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  1. 13 January, 08:44
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    a. - 191.7 J

    Explanation:

    The work done by a force is given by W = Fdcosθ where F = force applied and d = distance moved and θ is the angle between the force and distance moved.

    Here, F = frictional force = 14.2 N

    d = distance = 13.5 m

    and θ = 180° since the direction of the frictional force and distance are opposite.

    So, W = Fdcosθ = 14.2 * 13.5cos180° = - 191.7 J
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