How much force is needed to stretch a spring 1.2 m if the spring constant is 8.5 n/m? 7.1 n 7.3 n 9.7 n 10.2 n

Based on Hooke's Law, the force applied on the spring is equal to the product of the spring constant and the length sagged by the spring.

F = k x

where k is the spring constant

x is the length

Given from the problem is k = 8.5 n/m; and x = 1.2 m

So,

F = 8.5 N/m * 1.2 m

F = 10.2 N