A certain reaction has an activation energy of 67.72 kJ/mol. At what Kelvin temperature will the reaction proceed 4.00 times faster than it did at 353 K?

Question

June Wilson

Physics

7 December, 02:39

A certain reaction has an activation energy of 67.72 kJ/mol. At what Kelvin temperature will the reaction proceed 4.00 times faster than it did at 353 K?

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Jolee · Answer 1

T1 = 363 K

T2 = ?

R = 8.3145 J/mol K

K1 = 1

K2 = 4

Ea = 67.72 x 1000 = 67720 J/mol

T2 = 1 / (1/363) - (8.3145 / 67720) x ln (4 / 1)

T2 = 1 / 0.00258461502

T2 = 386.90 K