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9 May, 23:24

Manuel is holding a 5kg box how much force is he exerting on it

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  1. 9 May, 23:31
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    Mass = 5kg

    acceleration due to gravity = 9.8 m/s²

    Notice that we only have to work with vertical components,

    __Fn = ma (normal force Manuel exerts on box) (upward direction)

    __Fw = mg (weight of box) (downward direction)

    Because there is no change in motion, the sum of the vertical components should be equal to 0 or balance each other out. Therefore,

    ΣFy = Fn + (-Fw)

    0 = Fn + (-mg) [solve for Fn]

    mg = Fn

    (5kg) (9.8m/s²) =

    49 N = Fn = Force that Manuel is exerting on box (upward direction)
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