A large ball of steel has a mass of 500 kg. A smaller ball of steel of mass of 75 kg is placed some distance from the larger ball. The force of gravitation between them is given by F = GMm/r2

Compare, as a ratio, the force of gravity between the balls when they are placed 15 m apart and 20 m apart.

A) 9/16

B) 16/9

C) 4/3

D) 3/4

Question

Lena Stephenson

Physics

29 October, 17:39

A large ball of steel has a mass of 500 kg. A smaller ball of steel of mass of 75 kg is placed some distance from the larger ball. The force of gravitation between them is given by F = GMm/r2

Compare, as a ratio, the force of gravity between the balls when they are placed 15 m apart and 20 m apart.

A) 9/16

B) 16/9

C) 4/3

D) 3/4

+2

Answers (1)

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Fernanda Pineda · Answer 1

Force between the balls is: at 15 m : F (15) = G*500*75/15^2 = G*37500/225 at 20 m : F (20) = G*500*75/20^2 = G*37500/400 Then the ratio will be F (15) / F (20) = (G*37500/225) / (G*37500/400) = 400/225 = 16/9 Solution: Ratio is B) 16/9