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3 December, 19:53

A child walks 5m east, then 3m north, then 1m east. What is the magnitude of the child's displacement? What is the direction of the child's displacement?

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  1. 3 December, 19:54
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    You should first break up all the distances and directions into vectors and then add all horizontal vectors and verticle vectors.

    He goes, 5 + 1 m east = 6m East

    3 m north

    displacement = root (6^2 + 3^2) = 6.708m

    direction = arcTan (verticle/horizontal) = arcTan (3/6) = 26.565 degrees
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