Ask Question
7 February, 00:59

Water (2290 g) is heated until it just begins to boil. if the water absorbs 5.57*105 j of heat in the process, what was the initial temperature of the water?

+1
Answers (1)
  1. 7 February, 01:23
    0
    So the formula you will be needing looks like this:

    Q = m * c * (T_f - T_),

    where Q is the heat transferred to the water, m is the mass of the water, c is the specific heat capacity of water, and T_f and T_i are your final and initial temperatures, respectively. Now, you know that the final temperature is 100 degrees Celcius, because that is the temperature at which water boils. Rearranging the formula so that it gives you the initial temperature, you get:

    T_f - Q / (m*c) = T_i

    Putting in the numbers, we get:

    T_i = 41.8 degrees Celcius
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Water (2290 g) is heated until it just begins to boil. if the water absorbs 5.57*105 j of heat in the process, what was the initial ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers