What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand on it.) ?

Question

Kody Griffith

Physics

15 October, 15:44

What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand on it.) ?

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Medina · Answer 1

Since weight reflects the Normal Force of a surface to an object due to gravitational acceleration, if there is no physical surface to provide the Normal Force, the apparent weight would be 0N.