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4 January, 03:04

What acceleration will result when a 22N net force applied to an5 kg object? A 32 kg object?

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Answers (2)
  1. 4 January, 03:12
    0
    4.4 m/s2.6875M/S2

    Explanation:

    F=MXA

    A=F/M

    A=22/5 = 4.4M/S2

    A=22/32 =.6875M/S2
  2. 4 January, 03:23
    0
    Answer: 4.4 m/s2 and 0.69 m/s2

    Explanation: Force is the product of mass and acceleration

    a = F / m = 22N / 5kg = 4.4 m/s2

    a = F/m = 22 N / 32 kg = 0.69 m/s2
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