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10 January, 19:42

A worker pushes a box with a horizontal force of 40.0 N over a level distance of 4.0 m. If a frictional force of 27 N acts on the box in a direction opposite to that of the worker, what net work is done on the box

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  1. 10 January, 19:58
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    Work = (force) x (distance)

    The worker does (40N) x (4m) = 160 joules of work.

    Friction eats up (27N) x (4m) = 108 joules of that energy,

    generating 108 joules of heat.

    The remaining (160J - 108J) = 52 joules of energy moves the box.
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