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13 January, 00:26

If a Cu 2 + ion that is initially at rest accelerates through a potential difference of 12 V without friction, how much kinetic energy will it gain?

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  1. 13 January, 00:42
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    23,8eV

    Explanation:

    A=Uq=12 (V) * 2 * 1,6*10^-19 (C) = 3,84*10^-18 (J) = 23,8 (eV)
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