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10 October, 13:42

What is the average velocity of atoms in 1.00 mol argon at 275k? For m use 0.0399 kg

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Answers (2)
  1. 10 October, 13:56
    0
    414.0 m/s

    Explanation:

    A p E x
  2. 10 October, 14:03
    0
    Answer;

    414.0 m/s

    Explanation;

    From kinetic theory for an ideal gas ...

    Mean KE of a particle; ½mv² = 3kT/2

    For 1 mol of particles (L); Total KE = L½mv² = 3RT/2

    (Lm) ½v² = 3RT/2

    Lm = molar mass 0.0399kg, R = molar gas constant 8.30 J / (K. mol),

    T = Kelvin temp 275K

    v² = 3RT / Lm

    v² = 3 x 8.30 x 275 / 0.0399

    = 1.716^5

    v (rms) = √1.716^5

    v (rms) = 414.0 m/s
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