a wire carrying 1.5 A passes through a 48 mT magnetic field the wire is peremndicular to the field and makes a quarter circle turn radius 21 cm in the dield regeion. Find the magnitude and direction of the magnetic force

Wire is in the form of an arc of the size of a quarter of a circle. The distance between its two end

=√2 x 21 cm

= 29.7 cm

= 29.7 x 10⁻² m

Force on the arc in the magnetic field will be same as the straight line meeting its two ends.

Force = BIL

= 48 x10⁻³ x 1.5 x 29.7 x 10⁻²

= 2138.4 x 10⁻⁵ N.