In a particular location, the horizontal component of the earth's magnetic field has a magnitude of 1.50 10-5 t. an electron is shot vertically straight up from the ground with a speed of 2.40 106 m/s. what is the magnitude of the acceleration caused by the magnetic force? ignore the gravitational force acting on the electron.

Question

Shannon Gibbs

Physics

25 November, 21:10

In a particular location, the horizontal component of the earth's magnetic field has a magnitude of 1.50 10-5 t. an electron is shot vertically straight up from the ground with a speed of 2.40 106 m/s. what is the magnitude of the acceleration caused by the magnetic force? ignore the gravitational force acting on the electron.

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Aracely Oneal · Answer 1

Acceleration is the time rate of change of velocity. Acceleration is a vector, so this means it has both magnitude and direction. The length of the vector is its magnitude. Its direction is the direction of the vector.

The magnitude of the force is F=qvB.

According to Newton’s second law: F=ma, where m is the mass of the object, and a is its acceleration.

So, F=ma=qvB = > a=F/m,

a=qvB/m,

m in our case is the mass of an electron m=9.1x10^-31.

a = 1.60x10^-19C*2.40x10^6m/s*1.50x10^-5T/9