A roller coaster has a mass of 500 kg it drops from rest at the top of a hill that's 57 m tall how fast is it going when it reaches the bottom acceleration due to gravity is g=9.8 m/s

Answer Here, assuming no energy is dissipated by friction or air resistance, all the gravitational potential energy it has at the top of the hill is converted to kinetic energy at the bottom of the hill. Therefore, we have:

m

g

h

=

1

2

m

v

2

final

We want to solve for

v

, therefore

2

g

h

=

v

2

final

√

2

g

h

=

v

final

√

2

(

9.8

)

(

88

)

=

v

final

41.5

m

s

=

v

final

The answer is 33.4m/s ... i may be wrong but i'm sure that's the answer.