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22 November, 01:19

A rifle fires a 2.10 x 10^-2 kg pellet straight upward, because the pellet rests on a compressed spring when the trigger is is pulled. the spring has negligible mass and it is compressed by 9.10 x 10^-2 m from is unstrained length. the pellet rises to a maximum height of 6.10 m above its position on the compressed spring. ignoring air resistance determine the spring constant.

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  1. 22 November, 01:44
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    m = mass of pellet = 2.10 x 10⁻² kg

    x = compression of spring at the time launch = 9.10 x 10⁻² m

    h = height gained by the pellet above the initial position = 6.10 m

    k = spring constant

    using conservation of energy

    spring potential energy = gravitational potential energy of pellet

    (0.5) k x² = m g h

    inserting the values

    (0.5) k (9.10 x 10⁻²) ² = (2.10 x 10⁻²) (9.8) (6.10)

    k = 303.2 N/m
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