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31 July, 09:33

A crate with a mass of 186 kg sits flat on a horizontal surface. If the person slides the crate with constant velocity across the floor with a force of 273 N, what is the coefficient of kinetic friction between the crate and the floor?

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  1. 31 July, 09:48
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    0.15

    Explanation:

    mass, m = 186 kg

    Force, F = 273 N

    Let μ be the coefficient of friction

    As the block is moving with constant velocity so acceleration is zero.

    Let f be the friction force.

    F - f = ma

    273 - f = 0

    f = 273

    μ mg = 273

    μ x 186 x 9.8 = 273

    μ = 0.15

    Thus, the coefficient of friction is 0.15.
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