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5 September, 14:13

A 45.0-kg person steps on a scale in an elevator. The scale reads 460 n. What is the magnitude of the acceleration of the elevator?

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  1. 5 September, 14:21
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    The magnitude of the acceleration of the elevator is 0.422 m/s²

    Explanation:

    Lets explain how to solve the problem

    Due to Newton's Law ∑ Forces in direction of motion is equal to mass

    multiplied by the acceleration

    We have here two forces 460 N in direction of motion and the weight

    of the person in opposite direction of motion

    The weight of the person is his mass multiplied by the acceleration of

    gravity

    → W = mg, where m is the mass and g is the acceleration of gravity

    → m = 45 kg and g = 9.8 m/s²

    Substitute these values in the rule above

    → W = 45 * 9.8 = 441 N

    The scale reads 460 N

    → F = 460 N, W = 441 N, m = 45 kg

    → F - W = ma

    → 460 - 441 = 45 a

    → 19 = 45 a

    Divide both sides by 45

    → a = 0.422 m/s²

    The magnitude of the acceleration of the elevator is 0.422 m/s²
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