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15 May, 21:43

What is the rate at which work is done in lifting a 35-kilogram object vertically at a constant speed of 5.0 meters per second?

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  1. 15 May, 21:56
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    1.75 kW

    Explanation:

    First, the rate at which work is done is simply termed Power

    m = 35kg

    v = 5.0 m/s

    since the undergoes a vertical motion g = 10 m/s²

    F = W = mg = 35*10 = 350 N

    Power = Fv = 350*5 = 1750 Watt
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