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28 June, 11:46

A container with rigid walls is filled with 4.0 mol of air with Cv=2.5R Then the temperature is increased from 17 degrees C to 354 degrees C What is the change in internal energy? Let the ideal-gas constant R = 8.314 J / (mol • K). 337 J

28,000 J

7000 J

2800 J

+1
Answers (1)
  1. 28 June, 12:15
    0
    Internal energy = heat + work

    U = Q + W

    Since there's no change in volume (rigid walls), W = 0.

    U = Q

    U = n Cᵥ ΔT

    U = (4.0 mol) (2.5 * 8.314 J/mol/K) (354 C - 17 C)

    U = 28,000 J
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Home » Physics » A container with rigid walls is filled with 4.0 mol of air with Cv=2.5R Then the temperature is increased from 17 degrees C to 354 degrees C What is the change in internal energy? Let the ideal-gas constant R = 8.314 J / (mol • K).
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