A hot air balloon is traveling vertically upward at a constant speed of 2.8 m/s. When

it is 29 m above the ground, a package is

released from the balloon.

After it is released, for how long is the

package in the air? The acceleration of gravity

is 9.8 m/s^2.

Answer in units of s

What is its speed just before impact with the

ground?

Answer in units of m/s

Question

Luca Solomon

Physics

21 January, 17:20

A hot air balloon is traveling vertically upward at a constant speed of 2.8 m/s. When

it is 29 m above the ground, a package is

released from the balloon.

After it is released, for how long is the

package in the air? The acceleration of gravity

is 9.8 m/s^2.

Answer in units of s

What is its speed just before impact with the

ground?

Answer in units of m/s

+5

Answers (2)

Know the Answer?

Byron · Answer 1

why is your formula x=? if i'm reading it right the formula is the height of the object at time t. That being the case, set your setup (which looks right) equal to 0 and solve for t. This will tell you how long it takes to hit the ground. Plug this value of t into the forumla - 9.8t+2.8 and that will tell you the speed at time t.

Darius Keith · Answer 2

We can use the equation of motion:

2as = v² - u²; where s = 29 m, a = 9.8 m/s², u = - 2.8 m/s

v = √ (2 x 29 x 9.8 + 2.8²)

v = 24. 0 m/s