When a beam of light passes from substance 1 (index of refraction = 1.55) to substance 2, it has an angle of incidence of 39 ∘

and an angle of refraction of 24∘ What's the index of refraction of substance 2? For those who'll attempt the problem, Snells law should be used. k

Question

Zane Mccormick

Physics

9 October, 14:54

When a beam of light passes from substance 1 (index of refraction = 1.55) to substance 2, it has an angle of incidence of 39 ∘

and an angle of refraction of 24∘ What's the index of refraction of substance 2? For those who'll attempt the problem, Snells law should be used. k

+1

Answers (1)

Know the Answer?

Kassidy Wyatt · Answer 1

2.40

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the indexes of refraction, θ₁ is the angle of incidence (relative to the normal), and θ₂ is the angle of refraction (relative to the normal).

1.55 sin 39° = n sin 24°

n = 2.40

When a beam of light passes from substance 1 (index of refraction = 1.55) to substance 2, it has an angle of incidence of 39 ∘and an angle of refraction of 24∘ What's the index of refraction of substance 2? For those who'll attempt the problem, Snells law should be used. k

When a beam of light passes from substance 1 (index of refraction = 1.55) to substance 2, it has an angle of incidence of 39 ∘

and an angle of refraction of 24∘ What's the index of refraction of substance 2? For those who'll attempt the problem, Snells law should be used. k