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4 February, 02:21

What will the stopping distance be for a 3,000-kg car if - 3,000 N of force are applied when the car is traveling 10 m/s?

A. 30 m

B. 150,000 m

C. 50 m

D. 10 m

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Answers (1)
  1. 4 February, 02:26
    0
    F = force applied to stop the car = - 3000 N

    m = mass of the car = 3000 kg

    a = acceleration of the car = ?

    v₀ = initial velocity of the car before the force is applied to stop it = 10 m/s

    v = final velocity of the car when it comes to stop = 0 m/s

    d = stopping distance of the car

    acceleration of the car is given as

    a = F/m

    inserting the values

    a = - 3000/3000

    a = - 1 m/s²

    using the kinematics equation

    v² = v²₀ + 2 a d

    inserting the values

    0² = 10² + 2 (-1) d

    0 = 100 - 2 d

    2 d = 100

    d = 100/2

    d = 50 m

    hence the correct choice is

    C. 50 m
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