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16 August, 00:24

50 ml of milk at 5°C is added to 200 ml of hot chocolate at 95°C. What do you think the approximate new temperature is?

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  1. 16 August, 00:40
    0
    Answer;

    76.3°C

    Explanation;

    Considering the fact that;

    Specific heat capacity of the hot chocolate = 3.751 kJ/kg C°

    Specific heat capacity of milk is 3.93 kJ / (kg. C°)

    But;

    Heat gained by milk = Heat lost by hot chocolate

    If the final temperature is x, then

    Heat gained by milk

    = 0.05 * 3.93 * (x-5)

    = 0.1965x - 0.9825

    Heat lost by hot chocolate;

    = 0.2 * 3.751 * (95-x)

    = 71.269 - 0.7502x

    Therefore;

    0.1965x - 0.9825 = 71.269 - 0.7502x

    0.1965 x + 0.7502x = 71.269 + 0.9825

    0.9467 x = 72.2515

    x = 76.319 °C

    Approximately, the new temperature is 76.3°C
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