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17 June, 02:36

A second rock is thrown straight upward with a speed 4.750 m/s. If this rock takes 2.006 s to fall to the ground, from what height H was it released?

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  1. 17 June, 03:05
    0
    29.23 meters

    Explanation:

    H = ut + 1/2gt^2

    Initial velocity u = 4.750m/s

    time t = 2.006 secs

    Acceleration due to gravity g = 9.8m/s^2

    H =

    4.750 x 2.006 + 1/2 x 9.8 x (2.006) ^2

    9.53 + 1/2 x 9.8 x 4.02

    9.53 + 39.396/2

    9.53 + 19.698

    29.23 meters
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