The distance between two consecutive nodes of a standing wave is 21.9 cm. the hand generating the pulses moves up and down through a complete cycle 2.13 times every 3.65 s. find the velocity of the wave. answer in units of m/s.

Question

Kolton Freeman

Physics

4 November, 20:26

The distance between two consecutive nodes of a standing wave is 21.9 cm. the hand generating the pulses moves up and down through a complete cycle 2.13 times every 3.65 s. find the velocity of the wave. answer in units of m/s.

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Brayan Bowers · Answer 1

Distance between consecutive nodes is computed as d = lambda / 2, where 'lambda ' is the wavelength

so that lambda = 2 x d = 2 x 21.9 = 43.8 cm = 0.438 m further frequency n = 1/T = 2.13 / 3.65 = 0.5835 Hz

then speed of wave V = lambda x n = 0.438 x 0.5835 = 0.2556 m/sec = 25.56 cm/sec