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19 September, 16:29

The distance between neighboring singly charged sodium and chlorine ions in crystals of table salt (NaCl) is 2.82*10^-10m.

What is the attractive electric force between the ions?

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  1. 19 September, 16:48
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    2.897*10⁻⁹ N.

    Explanation:

    From coulomb's law,

    F = kqq'/r² ... Equation 1

    Where F = attractive force between the ions, q = charge on sodium ion, q' = charge on chlorine ion, r = distance between sodium and chlorine ion, k = coulomb's constant

    Given:q = 11*1.6*10⁻¹⁹ C, q' = 17*1.6*10⁻¹⁹ C, r = 2.82*10⁻¹⁰ m, k = 9*10⁹ Nm²/C²

    Substitute into equation 1

    F = 9*10⁹ (1.6*10⁻¹⁹) (1.6*10⁻¹⁹) / (2.82*10⁻¹⁰) ²

    F = 23.04*10⁹ (2.56*10⁻³⁸) / (7.9524*10⁻²⁰)

    F = (23.04*10⁻²⁹) / (7.9524*10⁻²⁰)

    F = 2.897*10⁻⁹ N.
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