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12 October, 08:07

You are pushing a crate horizontally with 100 N across a 10 m factory floor. If the force of friction on the crate is a steady 70 N, how much kinetic energy is gained by the crate

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  1. 12 October, 08:30
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    K E = 300 J

    Explanation:

    given,

    Force of pushing crate, F = 100 N

    distance of push = 10 m

    frictional force = 70 N

    kinetic energy is gained by the crate = ?

    using work energy theorem

    K E = work done

    K E = F. s

    K E = (100 - 70) x 10

    K E = 30 x 10

    K E = 300 J

    kinetic energy is gained by the crate is equal to 300 J.
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