A 0.80 kg basketball traveling upward at 5.0 m/s impacts an 8.0 10 kg tennis ball traveling downward at 5.0 m/s. The basketballâs velocity after the collision is 3.0 m/s upward. What is the velocity of the tennis ball after the collision?

The velocity of the tennis ball after the collision is 4.8 m/s downward.

Explanation:

When a basketball collides with tennis ball, the collision is perfectly elastic.

From the law of conservation of linear momentum, and considering opposite direction of two balls

m₁u₁ - m₂u₂ = m₁v₁ - m₂v₂

where;

m₁ is the mass of the tennis ball = 8.01 kg

u₁ is the initial velocity of the tennis ball = 5 m/s

m₂ is the mass of the basketball = 0.8 kg

u₂ is the initial velocity of the basketball = 5 m/s

v₁ is the final velocity of the tennis ball after collision = ?

v₂ is the final velocity of the basketball after collision = 3 m/s

m₁u₁ - m₂u₂ = m₁v₁ - m₂v₂

(8.01*5) - (0.8*5) = (8.01 * v₁) - (0.8*3)

40.05 - 4 = 8.01v₁ - 2.4

36.05 + 2.4 = 8.01v₁

38.45 = 8.01v₁

v₁ = 38.45/8.01

v₁ = 4.8 m/s

The positive sign, indicates downward velocity.

Therefore, the velocity of the tennis ball after the collision is 4.8 m/s downward.