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5 October, 16:23

A 5.00 Ω, a 10.0 Ω, and a 15.0 Ω resistor are connected in

series across a 90.0 V battery. What is the current in the

circuit?

a 5A

b

10 A.

с ЗА

d 8A

+1
Answers (1)
  1. 5 October, 16:42
    0
    Answer: Option C) 3A

    Explanation:

    Given that,

    Voltage = 90.0 Volts

    Current I = ?

    R1 = 5.0Ω

    R2 = 10.0Ω

    R3 = 15.0Ω

    Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

    i. e Rtotal = R1 + R2 + R3

    Rtotal = 5.0Ω + 10.0Ω + 15.0Ω = 30.0Ω

    Then, apply the formula for ohms law

    Voltage = Current x resistance

    V = I x Rtotal

    90.0V = I x 30.0Ω

    I = 90.0V / 30.0Ω

    I = 3 Amps (Amps is the unit of current)

    Thus, the current in the circuit is 3 Amps
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