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21 September, 20:34

The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2551 N2551 N with an effective perpendicular lever arm of 3.15 cm3.15 cm, producing an angular acceleration of the forearm of 115.0 rad / s2115.0 rad / s2. What is the moment of inertia of the boxer's forearm?

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  1. 21 September, 20:36
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    0.7 kg m²

    Explanation:

    F = force exerted applied by muscle in a professional boxer = 2551 N

    r = length of lever arm = 3.15 cm = 0.0315 m

    α = angular acceleration of the forearm = 115 rad/s²

    I = moment of inertia of the boxer's forearm

    τ = Torque applied by muscle in a professional boxer

    Torque is given as

    τ = I α = r F

    Inserting the values

    I (115) = (0.0315) (2551)

    I = 0.7 kg m²
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