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26 June, 12:38

A 4148-kg truck traveling with a velocity of 12 m/s due east collides head-on with a 898-kg car traveling with a velocity of 40 m/s due west. The two vehicles stick together after the collision. Determine the momentum of the 4148-kg truck and the 898-kg car prior to the collision.

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  1. 26 June, 12:47
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    49776 kgm/s

    - 35920 kgm/s

    Explanation:

    Consider east direction as positive direction of motion and west as negative direction of motion

    M = mass of the truck = 4148 kg

    V = velocity of the truck in the east direction = 12 m/s

    P = Momentum of the truck = ?

    Momentum of the truck is given as

    P = M V

    P = (4148) (12)

    P = 49776 kgm/s

    m = mass of the car = 898 kg

    v = velocity of the car in the west direction = - 40 m/s

    p = Momentum of the car = ?

    Momentum of the truck is given as

    p = m v

    p = (898) ( - 40)

    p = - 35920 kgm/s
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