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4 January, 12:14

A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box? A) 1.3 N B) 1.31 N C) 9.7 N D) 23.1 N

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  1. 4 January, 12:20
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    The sum of all forces=m (mass) times a (acceleration). F=5.5 (kg) * 4.2 (m/s^2) = 23.1N or D.
  2. 4 January, 12:27
    0
    The Answer is D)

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