A spherical conductor with a 0.103 m radius is initially uncharged. How many electrons should be removed from the sphere in order for it to have an electrical potential of 4.50 kV at the surface

capacitance of the capacitor C = 4πε₀R

= 1 x. 103 / (9 x 10⁹) [ 1 / 4πε₀ = 9 x 10⁹. ]

=.0114 x 10⁻⁹ F

potential V = 4.5 x 10³ v

charge Q = CV

.0114 x 10⁻⁹ x 4.5 x 10³

=.0515 x 10⁻⁶ C

charge on one electron = 1.6 x 10⁻¹⁹

no of electrons to be removed

=.0515 x 10⁻⁶ / 1.6 x 10⁻¹⁹

=.032 x 10¹³

3.2 x 10¹¹ electrons.