John Doe gets to go to the race track for a day. The track he is driving on is a perfect circle 750m in radius. If he is driving at 30m/s around the track, what is the centripetal acceleration experienced by the car, and what is the rotational velocity of the car?

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24 September, 18:47

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Pierce Sloan · Answer 1

Centripetal acceleration = v²/r = 30²/750 = 1.2 m/s².

Rotational velocity = v/r = 30/750 = 0.04 rad/s