Calculate the amount of heat (in kJ) required to convert 97.6 g of water to steam at 100° C. (The molar heat of vaporization of water is 40.79 kJ/mol.)

Question

Aurora Burns

Physics

17 May, 07:12

Calculate the amount of heat (in kJ) required to convert 97.6 g of water to steam at 100° C. (The molar heat of vaporization of water is 40.79 kJ/mol.)

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Answers (1)

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Blake Griffith · Answer 1

221.17 kJ

Explanation: Note the heat of vaporization is in kJ/mol, then to determine the number of moles of water: divide the mass by 18. Then multiply the number of moles by the molar heat of vaporization of water.

N = 97.6 : 18

Q=molar heat * moles

Q = (40.79) * (97.6 : 18)

This is approximately 221.17 kJ