For a planet orbiting the sun, r p is the distance from the sun to the perihelion and r a is the distance from the sun to the aphelion. What is a planet's orbital eccentricity if r p is equal to 0.45r a?

A. 1.45

B. 0.55

C. 0.38

D. 2.64

Where is the sun located on Earth's elliptical orbit?

A. at the center of the two foci

B. at a focus

C. at the aphelium

D. at the perihelium

A satellite orbiting Earth at an orbital radius r has a velocity v. Which represents the velocity if the satellite is moved to an orbital radius of 4r?

A. 1/4v

B. 4v

C. 1/2v

D. 2v

Question

Bambi

Physics

13 February, 08:19

For a planet orbiting the sun, r p is the distance from the sun to the perihelion and r a is the distance from the sun to the aphelion. What is a planet's orbital eccentricity if r p is equal to 0.45r a?

A. 1.45

B. 0.55

C. 0.38

D. 2.64

Where is the sun located on Earth's elliptical orbit?

A. at the center of the two foci

B. at a focus

C. at the aphelium

D. at the perihelium

A satellite orbiting Earth at an orbital radius r has a velocity v. Which represents the velocity if the satellite is moved to an orbital radius of 4r?

A. 1/4v

B. 4v

C. 1/2v

D. 2v

+2

Answers (1)

Know the Answer?

Coleman Dean · Answer 1

To calculate forn the ecentricity we use this formula

e = Ra - Rp / Ra + Rp

= 0.55

B = focus

Kepler's First Law: each planet's orbit about the Sun is an ellipse. The Sun's center is always located at one focus of the orbital ellipse. The Sun is at one focus. The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit.

c=1/2v