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9 June, 02:36

A 120 kg quarterback is stationary in the "pocket" and hit by a defensive tackle with 4000 Newtons of force. What acceleration did the quarterback experience after being hit

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  1. 9 June, 03:03
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    Answer: 33.3 m/s^2

    Explanation:

    Here we need to use the second Newton's law.

    F = m*a

    Force equals mass times the acceleration.

    Here we know that the force is F = 4000 N, and the mass is 120kg, then the acceleration must be:

    4000 N = 120kg * a

    a = (4000/120) m/s^2 = 33.3 m/s^2
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