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14 June, 18:18

A 0.025-kilogram bullet is fired from a rifle by an unbalanced force of 200. newtons. if the force acts on the bullet for 0.1 second, what is the maximum speed attained by the bullet?

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  1. 14 June, 18:21
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    First, calculate the acceleration of the bullet by making use of the second law of motion by Newton which can be translated in equation as,

    F = m x a

    Solving for a,

    a = F/m

    Substituting the known values,

    a = (200 N) / (0.025 kg) = 8000 m/s²

    The maximum velocity of the bullet is the product of the acceleration and the given time.

    v = (8000 m/s²) (0.1 s) = 800 m/s

    Answer: 800 m/s
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