A man pushes a cart with force of 120-N at an angle of 50 degrees with the ground. If he walks a horizontal displacement of 20-m going to cashier who's much work is done!

The answer to your question is Work = 1542.7 J

Explanation:

Data

Force = 120N

angle = 50°

distance = 20 m

Work = ?

Process

1. - Find the horizontal component of the force

cos Ф = adjacent side / hypotenuse

Solve for adjacent side

Adjacent side = hypotenuse x cosФ

Adjacent side = 120 x cos 50

Adjacent side = 77.13 N

2. - Find the Work

Formula

Work = Force x distance

Substitution

Work = 77.13 x 20

Simplification and result

Work = 1542.7 J