Ask Question
18 July, 07:33

The active element of a certain laser is made of a glass rod 31.0 cm long and 1.30 cm in diameter. Assume the average coefficient of linear expansion of the glass is equal to 9.00 10-6 (°C) - 1. The temperature of the rod increases by 62.0°C. What is the increase in its length?

(a) What is the increase in its length?

(b) What is the increase in its diameter?

(c) What is the increase in its volume?

+4
Answers (1)
  1. 18 July, 07:40
    0
    (a) ΔL=0.172 mm

    (b) Δd=7.254*10⁻³mm

    (c) ΔV=21.92 mm

    Explanation:

    Given data

    L (length) = 31.0cm→310mm

    d (diameter) = 1.30cm→13 mm

    α (Coefficient) = 9.00*10⁻⁶ °C⁻¹

    T (Temperature) = 62 °C

    (a) ΔL=?

    (b) Δd=?

    (c) ΔV=?

    Solution

    For (a) ΔL part

    ΔL=α*LΔT

    ΔL = (9.00*10⁻⁶) * (310) * (62)

    ΔL=0.172 mm

    For (b) Δd part

    Area is π*r² but diameter is just 2π*r

    Δd=α*dΔT

    Δd = (9.00*10⁻⁶) * (13) * (62)

    Δd=7.254*10⁻³mm

    For (c) ΔV part

    Volume is Lπ*r² and α is 3α

    ΔV=3α (Lπ*r²) * 62

    ΔV=3 * (9.00*10⁻⁶) * (310 * (13/2) ²) * 62

    ΔV=21.92 mm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The active element of a certain laser is made of a glass rod 31.0 cm long and 1.30 cm in diameter. Assume the average coefficient of linear ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers